For the same objective, the ratio of least separation between two points to be distiguised by a microscope for light of `5000 Å` and electrons acclerated through 100V used as illuminating substance is __________ (neraly)

Explanation

The limit of resolution of a microscope is `d = (lambda)/(2 sin theta)`
where `2 theta` is the angle of cone of light rays entering the objective of the microscope.
For light, `lambda_(1) = 5000 Å`
For electrons accelerated through `100 V`, de Broglie wavelength, `lambda_(2) = (12.27)/(sqrt(100))Å = 1.227 Å`. ltbr? As `(2 sin theta)` is same in the two cases, therefore, `(d_(1))/(d_(2)) = (lambda_(1))/(lambda_(2)) = (5000)/(1.227) = 4075`