The velocity of sound in air is 333 m/s. the length of the an open pipe, in order to produce second overtone of frequency 999Hz in it, will be

The velocity of sound in air is 333 m//s . The length of an open pipe, in order to produce second overtone of frequency 999 Hz in it, will be

The speed of sound in air is 333 m/s. The fundamental frequency of the open pipe is 333 Hz. The second oevertone of the open organ pipe can be produced with a pipe of length

Velocity of sound in air is 332 m//sec . The shortest length of an open pipe which will resonate with a tuning fork of frequency 166Hz is

Velocity of sound in air is 332 m//sec . The shortest length of an open pipe which will resonate with a tuning fork of frequency 166Hz is

The velocity of sound in air is 330 m//s . Then the frequency that will resonate with an open pipe of length 1m is –

The velocity of sound in air is 320 m*s^(-1) . The length of a closed pipe is 1 m . If the end error in nelected, which of the following frequencies produce resonance with the air column of the pipe : 80 Hz // 240 Hz // 320 Hz // 400 Hz

The velocity of sound in air is 320ms^(-1) . An open organ pipe 40 cm long resonates at a frequency of 1200 Hz. Which overtone is it ?

The velocity of sound in air is 320ms^(-1) . An open organ pipe 40 cm long resonates at a frequency of 1200 Hz. Which overtone is it ?

The velocity of sound in air is 320 ms^-1 . A closed organ pipe of length 20 cm resonates at a frequency of 1200 Hz. Which overtone is it?

Velocity of sound in air is 333 m/s .Length of air column in pipe is 33.3 cm . Calculate the frequency of the 5th overtone , if the pipe is open at both the ends.