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Two metallic plates P (collector) and Q ...

Two metallic plates P (collector) and Q (emitter) are separated by a distance of 0.10 meter. These are connected through an ammeter without any cell. A magnetic field B exists parallel to the plates. Light of wavelength between `4000Å and 6000Å` fall on the plate whose work function is 2.39eV. Calculate the minimum value of B for which the current registered with ammeter is zero. Use, `h=6.6xx10^(-34)Js, e=1.6xx10^(-19)C`

Text Solution

Verified by Experts

Energy of the incident photon of light of wave length `6000Å` is
`E=(hc)/lambda=((6.6xx10^(-34))xx(3xx10^(8)))/(6000xx1.6xx10^(-19))eV=2.01eV`
Since this value of energy is less than work function `(=2.39eV)` of the metal, hence no photoelectron is emitted for light of wavelength `6000Å` Since the energy of photon of light of wavelength `4000Å` is greater than 2.39 eV , so photoelectric emission takes place with its helt.
Maximum K.E. of the emitted photoelectron is
`K_(max)=1/2mv_(max)^(2)=(hc)/lambda-phi_(0)= ((6.6xx10^(-34))xx(3xx10^(8)))/(4000xx10^(-10)xx1.6xx10^(-19))-2.39eV`
`=3.1-2.39=0.71 eV=0.71xx1.6xx10^(-19)J`
`v_(max)=[(2xx0.71xx1.6xx10^(-19))/(9.1xx10^(-31))]^(1//2)=5xx10^(5)m//s`
For zero constantl, `(mv^(2))/r=evB or B=(mv)/(er)=((9.1xx10^(-31))xx5xx10^(5))/((1.6xx10^(-19))xx0.1)=2.86xx10^(-5)T`
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In an experiment on photoelectric effect, the emitter and the collector plates are placed at a separation of 10cm and are connected through an ammeter without any cell. A magnetic field B exists parallel to the plates. The work function of the emitter is 2.39 e V and the light incident on it has wavelengths between 400nm and 600nm. Find the minimum value of B for which the current registered by the ammeter is zero. Neglect any effect of space charge.

In a photocell the plates P and Q have a separation of 5 cm, which are connected through a galvanometer without any cell. Bichromatic light of wavelengths 4000 Å and 6000 Å are incidenton plate Q whose work- functionis 2.39 eV. If a uniform magnetic field B exists parallel to the plates, find the minimum value of B for which the galvanometer shows zero deflection.

Knowledge Check

  • Two metallic plates P(collector) and Q (emitter) are separated by a distance of 0.2 m. These are connected through an 0.2 m. These are connected through an ammeter without any cell. A magnetic field B exists parallel to the plates. Light of wavelengths between 2000 Å and 3000 Å fall of the plate Q whose work function is 2.22 eV. The minimum value of B for which the current registered with ammeter is zero, is

    A
    `3.8 xx10^-5 T`
    B
    `4.7 xx10^-5 T`
    C
    `6.7 xx10^-5 T`
    D
    `8.6 xx10^-5 T`
  • A radiation of wave length 2500A^(0) is incident on a metal plate whose work function is 3.5eV . Then the potential required to stop the fastest photo electrons emitted by the surface is (h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)

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    `1.86V`
    B
    `3.00V`
    C
    `1.46V`
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    `2.15V`
  • Light of wavelength 4000Å is allowed to fall on a metal surface having work function 2 eV. The maximum velocity of the emitted electrons is (h=6.6xx10^(-34)Js)

    A
    `1.35xx10^(5)ms^(-1)`
    B
    `2.7xx10^(5)ms^(-1)`
    C
    `6.2xx10^(5)ms^(-1)`
    D
    `8.1xx10^(5)ms^(-1)`
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