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The slope of frequency of incident light...

The slope of frequency of incident light and stopping potential for a given surface will be

A

`h`

B

`h//e`

C

`eh`

D

`e`

Text Solution

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The correct Answer is:
To find the slope of the graph of frequency of incident light versus stopping potential for a given surface, we can use Einstein's photoelectric equation. Let's derive the relationship step by step. ### Step-by-Step Solution: 1. **Understanding the Photoelectric Effect**: The photoelectric effect occurs when light of sufficient frequency strikes a material and causes the ejection of electrons. The energy of the incident photons must be greater than the work function of the material for electrons to be emitted. 2. **Einstein's Photoelectric Equation**: The equation is given by: \[ E \cdot V_0 = h \nu - \phi_0 \] where: - \(E\) is the charge of the electron, - \(V_0\) is the stopping potential, - \(h\) is Planck's constant, - \(\nu\) is the frequency of the incident light, - \(\phi_0\) is the work function of the material. 3. **Rearranging the Equation**: We can rearrange the equation to express \(V_0\) in terms of \(\nu\): \[ E \cdot V_0 = h \nu - \phi_0 \] Dividing through by \(E\): \[ V_0 = \frac{h}{E} \nu - \frac{\phi_0}{E} \] 4. **Identifying the Linear Relationship**: The equation \(V_0 = \frac{h}{E} \nu - \frac{\phi_0}{E}\) is in the form of \(y = mx + c\), where: - \(y\) is the stopping potential \(V_0\), - \(x\) is the frequency \(\nu\), - \(m\) (the slope) is \(\frac{h}{E}\), - \(c\) (the y-intercept) is \(-\frac{\phi_0}{E}\). 5. **Conclusion**: The slope of the graph of frequency of incident light versus stopping potential is: \[ \text{slope} = \frac{h}{E} \] ### Final Answer: The slope of the frequency of incident light and stopping potential for a given surface will be \(\frac{h}{E}\).
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The graph between frequency of incident radiations and stopping potential for a given photosensitive material as follows. What information can be obtained from the value of the intercept on the potential axis ?

Sketch a graph between frequency of incident radiations and stopping potential for a given photosenstive material. What information can be obtained from the value of the intercept on the potential axis? A source of light of frequency greater than the threshold frequency is placed at a distance of 1m from the cathode of a photocell. The stopping potential is found to be V. If the distance of the light source from the cathode is reduced, explain giving reasons, what change will you observe in the (i) photoelectric current (i) stopping potential?

Knowledge Check

  • In a photoelectric experiment, the graph of frequency v of incident light (in Hz) and stopping potential V (in V) is as shown in the figure. Planck's constant is (e is the elementary charge)

    A
    `e(ab)/(bc)`
    B
    `e(cb)/(ac)`
    C
    `e(ac)/(bc)`
    D
    `e(ac)/(ab)`
  • The photoelectric work function of the emitter of a photocell is 3.63 eV . The frequency of incident light radiation if the stopping potential of the emitter is 3 volt , is

    A
    `1. 1 xx 10^(15) ` Hz
    B
    `6.6 xx 10^(15)` Hz
    C
    `1.6 xx 10^(15)` Hz
    D
    `6.1 xx 10^(15)` Hz
  • In photoelectric effect the slope of stop of stopping potential versus frequency of incident light for a given surface will be

    A
    ` h e^(-1)`
    B
    e h
    C
    e
    D
    h
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    The stopping potential (v_0) varies linearly with the frequency (v)of the incident radiation for a given photosensitive surface with the slope remaining the same for different surface . Given reason.

    Choose the correct option for the graph between the frequency of incident light and the stopping potential.

    Assertion : The stopping potential depends on the frequency of incident light. Reason : The stopping potential is related to maximum kinetic energy by eV_(0)=K_(max) .

    Assertion: If frequency of incident light is doubled, the stopping potential will also become two times Reason: Stopping potential is given by V_0 = (h)/(e ) (v-v_0)

    Monochromatic light of frequency f_(1) incident on a photocell and the stopping potential is found to be V_(1) . What is the new stopping potential of the cell if it is radiated by monochromatic light of frequency f_(2) ?