Two particles `A_(1) and A_(2)` of masses `m_(1), m_(2) (m_(1)gtm_(2))` have the same de-broglie wavelength. Then

Options

A. their momenta are the same
B. their energies are the same
C. energy of `A_(1)` is less than the energy of `A_(2)`
D. energy of `A_(1)`, is more than the energy of `A_(2)`

Answer

a,c

Explanation

As `lambda=h/p or p=h/lambda or prop 1/lambda :. (p_(1))/(p_(2))=(lambda_(2))/(lambda_(2))=lambda/lambda=1/1 or p_(1)=p_(2)`
`E=1/2 (p^(2))/m=1/(2m) (h^(2))/(lambda^(2)) ( :' p=h/lambda)`
So, `E prop 1/m :. (E_(1))/(E_(2))=(m_(2))/(m_(1)) lt 1` or `E_(1) lt E_(2)`