Monochromatic light of frequency `f_(1)` incident on a photocell and the stopping potential is found to be `V_(1)`. What is the new stopping potential of the cell if it is radiated by monochromatic light of frequency `f_(2)`?

Options

A. `V_(1)-h/e(f_(2)-f_(1))`
B. `V_(1)+h/e(f_(2)+f_(1))`
C. `V_(1)-h/e(f_(2)+f_(1))`
D. `V_(1)+h/e(f_(2)-f_(1))`

Answer

d

Explanation

Using Einstein's photoelectric equation, we have
`eV_(0)=hf-phi(0)`
As per question,
`eV_(1)=hf_(1)-phi(0)` and `eV_(2)=hf_(2)-phi(0)`
`:. E(V_(2)-V_(1))=h(f_(2)-f_(1))`
or `eV_(2)=hf_(2)-hf_(1)+eV_(1)`
or `V_(2)=h/e(f_(2)-f_(1))+V_(1)`