The momentum of a photon of an electromagnetic radiation is `4.3xx10^(-29)Kgm//s`. What is the frequency of the associated wave? `[h=6.6xx10^(-34)Js ,c=3xx10^(8)m//s]`

Options

A. `1.5xx10^(13)Hz`
B. `1.95xx10^(13)Hz`
C. `5.6xx10^(13)Hz`
D. `3.9xx10^(13)Hz`

Answer

B

Explanation

Here, `p=4.3xx10^(-29)Kg m//s, h=6.6xx10^(-34)Js`,
`c=3xx10^(8)m//s`
As `p=E/c=(hv)/c`
or `v=(pc)/h=(4.3xx10^(-29)xx3xx10^(8))/(6.6xx10^(-34))`
`=1.95xx10^(13)Hz`