If `lambda_(1) and lambda_(2)` denote the wavelength of de-broglie waves for electron in Bohr's first and second orbits in the hydrogen atom, then `lambda_(1)//lambda_(2)` will be

Options

A. `2`
B. `1//2`
C. `4`
D. `1//4`

Answer

b

Explanation

According to de-Broglie a stationary orbit is that which contains an integral number of de-broglie waves associated with the revolving electrons. Therefore, in first orbit `lambda_(1)=1xxlambda` and in second orbit `lambda_(2)=2xxlambda`.
Hence, `(lambda_(1))/(lambda_(2))=lambda/(2lambda)=1/2`