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The de-Broglie wavelength of the tennis ...

The de-Broglie wavelength of the tennis ball of mass 60g moving with a velocity of `10m//s` is approx.: (Plank's constant `h=6.63xx10^(-34)Js`)

A

`10^(-33) m`

B

`10^(-31) m`

C

`10^(-16) m`

D

`10^(-25) m`

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The correct Answer is:
To find the de-Broglie wavelength of a tennis ball with a mass of 60 g moving at a velocity of 10 m/s, we can use the de-Broglie wavelength formula: \[ \lambda = \frac{h}{mv} \] where: - \(\lambda\) is the de-Broglie wavelength, - \(h\) is Planck's constant (\(6.63 \times 10^{-34} \, \text{Js}\)), - \(m\) is the mass of the object in kg, - \(v\) is the velocity of the object in m/s. ### Step 1: Convert the mass from grams to kilograms The mass of the tennis ball is given as 60 g. To convert grams to kilograms: \[ m = 60 \, \text{g} = 60 \times 10^{-3} \, \text{kg} = 0.060 \, \text{kg} \] ### Step 2: Use the given velocity The velocity of the tennis ball is given as 10 m/s, which is already in SI units. \[ v = 10 \, \text{m/s} \] ### Step 3: Substitute values into the de-Broglie wavelength formula Now we can substitute the values of \(h\), \(m\), and \(v\) into the de-Broglie wavelength formula: \[ \lambda = \frac{6.63 \times 10^{-34} \, \text{Js}}{(0.060 \, \text{kg})(10 \, \text{m/s})} \] ### Step 4: Calculate the denominator First, calculate the denominator: \[ mv = (0.060 \, \text{kg})(10 \, \text{m/s}) = 0.60 \, \text{kg m/s} \] ### Step 5: Calculate the de-Broglie wavelength Now substitute the value of \(mv\) back into the equation: \[ \lambda = \frac{6.63 \times 10^{-34} \, \text{Js}}{0.60 \, \text{kg m/s}} = 1.105 \times 10^{-33} \, \text{m} \] ### Step 6: Round the result For simplicity, we can round this to: \[ \lambda \approx 1.1 \times 10^{-33} \, \text{m} \] ### Conclusion Thus, the de-Broglie wavelength of the tennis ball is approximately: \[ \lambda \approx 1.1 \times 10^{-33} \, \text{m} \]

To find the de-Broglie wavelength of a tennis ball with a mass of 60 g moving at a velocity of 10 m/s, we can use the de-Broglie wavelength formula: \[ \lambda = \frac{h}{mv} \] where: - \(\lambda\) is the de-Broglie wavelength, ...
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