`lambda_(e),lambda_(p)` and `lambda_(alpha)` are the de-Broglie wavelength of electron, proton and `alpha` particle. If all the accelerated by same potential, then

Options

A. `lambda_(e) lt lambda_(p) lt lambda_(alpha)`
B. `lambda_(e) lt lambda_(p) gt lambda_(alpha)`
C. `lambda_(e) gt lambda_(p) gt lambda_(alpha)`
D. `lambda_(e) gt lambda_(p) lt lambda_(alpha)`

Answer

c

Explanation

`lambda=h/(sqrt(2mqV))` or `lambda prop1/(sqrt(mq))`
`:. lambda_(e): lambda_(p): lambda_(alpha)=1/(sqrt(m_(e)q_(e))):1/(sqrt(m_(p)q_(p))):1/(sqrt(m_(alpha)q_(alpha)))`
`=1/(sqrt((m_(p)//1840)xxe)):1/(sqrt(m_(p)xxe)):1/(sqrt(4m_(p)xx2e))`
`:. lambda_(e)gt lambda_(p)gt lambda_(alpha)`