The frequency and intensity of a light source are both doubled. Consider the following statements
A. The saturation photocurrent remains almost the same
B. The maximum kinetic energy of the photoelectrons is double

Options

A. The saturation photocurrent gets double
B. The saturation photocurrent remains almost the same
C. The maximum K.E. of the photoelectron is more than doubled
D. The maximum K.E. of the photoelectrons gets double.

Answer

a,c

Explanation

Saturation photoelectric current depends upon the intensity of the incident light.
As `K_(max)=hv-phi_(0)`. If `v` becomes double, then `K_(max)` becomes more than double as
`2hv-phi_(0)gt2(hv-phi_(0))`