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Calculate the longest and shortest wavel...

Calculate the longest and shortest wavelength in the Balmer series of hydrogen atom. Given Rydberg constant =`1.0987xx10^7m^-1`.

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To calculate the longest and shortest wavelength in the Balmer series of the hydrogen atom, we will use the Rydberg formula: \[ \frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] where: - \( \lambda \) is the wavelength, ...
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Calculate the longest and shortest wavelength in the Balmer series of Hydrogen atom. Rydberg constant = 1.0987xx 10^7 m^(-1) .

Which is the shortest wavelength in the Balmer series of hydrogen atoms ?

Knowledge Check

  • The shortest wavelength of Balmer series of H-atom is

    A
    `4/R`
    B
    `36/(5R)`
    C
    `1/R`
    D
    `3/(4R)`
  • The series limit wavelength of the Balmer series for the hydrogen atom is

    A
    `1/R`
    B
    `4/R`
    C
    `9/R`
    D
    `16/R`
  • The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is,

    A
    `25/9`
    B
    `17/6`
    C
    `9/5`
    D
    `5/4`
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