The energy of electron in 1st orbit of hydrogen atom is `-13.6 eV`. What will be the energy of doubly ionised `._(3)Li^(7)` atom in the first orbit?
Text Solution
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for `._3Li^7`, `Z=3` and `n=1` for first orbit `E'=E(z^2)/(n^2)=-13.6xx(3^2)/(1^2)=-122.4eV`
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