Calculate mass defect, binding energy and binding energy per nucleon for a lithium nucleus `(._3Li^7)` taking its mass =7.000000a.m.u. Mass proton=1.007825 a.m.u. and mass of neutron =1.008665 a.m.u. Take 1a.m.u. =931.5 MeV.
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To solve the problem, we will follow these steps:
### Step 1: Determine the number of protons and neutrons in the lithium nucleus
The lithium nucleus is represented as \( _3Li^7 \). Here, the atomic number (Z) is 3, which indicates the number of protons. The mass number (A) is 7, which is the total number of protons and neutrons.
- Number of protons (Z) = 3
- Mass number (A) = 7
- Number of neutrons (N) = A - Z = 7 - 3 = 4
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