The energy released in a nuclear fission process is `4.5xx10^(11)J`. Where in total mass involved is one gram. Calculate the percentage of mass defect in the process.
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Here, `E=4.5xx10^(11)J, m=1"gram"` Let the mass defect be `Delta m` `:. E=(Delta m) C^2` `Delta m=E/(C^2)=(4.5xx10^(11))/((3xx10^8)^2)=0.5xx10^(-5)kg` `(Delta m)/m xx 100=(0.5 xx 10^-5)/(10^-3) xx 100%=0.5%`
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