In a Geiger Marsden experiment, calculate the distance of closest approach to the nucleus of Z=80, when an `alpha`-particle of `8 MeV` energy impings om it before it comes momentarily to rest and reverses its direction.
Text Solution
AI Generated Solution
To solve the problem of calculating the distance of closest approach to the nucleus of an atom with atomic number \( Z = 80 \) when an alpha particle with energy \( 8 \, \text{MeV} \) approaches it, we will use the concept of electrostatic potential energy and the formula for the distance of closest approach in a Coulombic interaction.
### Step-by-Step Solution:
**Step 1: Convert Energy from MeV to Joules**
The energy of the alpha particle is given as \( 8 \, \text{MeV} \). We need to convert this energy into Joules.
...
Topper's Solved these Questions
ATOMS AND NUCLEI
PRADEEP|Exercise (II) very short answer 16|1 Videos
ATOMS AND NUCLEI
PRADEEP|Exercise (I) Short Answer questions 1|1 Videos
COMMUNICATION SYSTEMS
PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos
Similar Questions
Explore conceptually related problems
In a Geiger- Marsden experiment, calculate the distance of closest approach to the nucleus of Z=80, when an alpha particle of 8 Me V energy impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the alpha- particle is doubled ?
In a Geiger - Marsden experiment, calculate the distance of closest approach to the nucleus of Z=75, when an alpha - particle of 5 Me V enery impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the alpha -particle is doubled ?
In the original experiment, Geiger and Marsden calculated the distance of closest approach to the gold nucleus (Z=79)- of a 7.7MeV alpha particle before it comes momentarily to rest and reverses its direction. What is its value?
In a geiger - marsden experiment. Find the distance of closest approach to the nucleus of a 7.7 me v alpha - particle before it comes momentarily to rest and reverses its direction. (z for gold nucleus = 79) .
What is the distance of closest approach to the nucleus for an alpha -particle of energy 5J MeV which undergoes scattering in the Gieger-Marsden experiment.
What is the distance of closest approach to the nucleus of an alpha partile which undergoes scattering by 180^(@) is geiger-marsden experiment?
In Rutherford experiment, a 5.3 MeV alpha -particle moves towards the gold nucleus (Z=79). How close does the alpha -particle to get the centre of the nucleus, before it comes momentarily to rest and reverses its motion? ( epsi_(0)=8.8xx10^(-12)F//m )
Calculate the distance of closest approach for a proton with energy 3 MeV approaching a gold nucleus.
In scattering experiment, find the distance of closest approach, if a 6 MeV alpha - particle is used
PRADEEP-ATOMS AND NUCLEI-Assertion- Reason type question 12