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What is the size of nucleus with Z=29 wh...

What is the size of nucleus with Z=29 when an alpha particle of 12.5MeV kinetic energy retrace its path on colliding with the nucleus?

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Here, Z=29,
`E=12.5MeV=12.5xx1.6xx10^(-13)J`
Size of nucleus =`r_0=(2Ze^2)/(4pi in_0(E))`
`=(9xx10^9xx2xx29(1.6xx10^(-19))^2)/(12.5xx1.6xx10^(-13))`
`r_0=6.68xx10^(-15)m`
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