In Rutherford's nuclear model of the atom, the nucleus (radius about `10^(-15)m`) is analogous to the sum about which the electron moves in orbit (radius about `10^(-10)m`) like the earth orbits around the sun. If the dimensions of the solar system had the same proportions as those of the atom, would the earth be closer to or further away form the sun than actually it is ? The radius of earth's orbit is about is `1.5xx10^(11)m`. The radius of the sun is taken as `7xx10^8m`.

Explanation

To solve the problem, we need to analyze the proportions of the sizes involved in both the atomic model (Rutherford's model) and the solar system. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the sizes in the atomic model
- The radius of the nucleus is given as \( r_n = 10^{-15} \) m.
- The radius of the electron's orbit is given as \( r_e = 10^{-10} \) m.

### Step 2: Identify the sizes in the solar system
- The radius of the sun is given as \( r_s = 7 \times 10^8 \) m.
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