The total energy of an electron in second excited state of hydrogen atom is -1.51eV. Calculate (i) KE of electron (ii) PE of electron in this state.
Text Solution
AI Generated Solution
To solve the problem, we need to calculate the kinetic energy (KE) and potential energy (PE) of the electron in the second excited state of the hydrogen atom, given that the total energy (E) is -1.51 eV.
### Step-by-Step Solution:
1. **Understanding Total Energy**:
The total energy (E) of an electron in a hydrogen atom is given by the formula:
\[
E = KE + PE
...
Topper's Solved these Questions
ATOMS AND NUCLEI
PRADEEP|Exercise (II) very short answer 16|1 Videos
ATOMS AND NUCLEI
PRADEEP|Exercise (I) Short Answer questions 1|1 Videos
COMMUNICATION SYSTEMS
PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos
Similar Questions
Explore conceptually related problems
The total energy of an electron in the first excited state of hydrogen atom is -3.4 eV. (a) What is kinetic energy of electron in this state? (ii) What is potential energy of electron in this state? (c) Which of the answers above would change if the choice of zero of potential energy is changed?
(a) The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^(-11) m. Calculate its radius in n =2 orbit. (b) The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. Find out its (i) kinetic energy and (ii) potential energy in this state.
Total energy of electron in an excited state of hydrogen atom is -3.4 eV . The kinetic and potential energy of electron in this state.
Energy of electron in first excited state in Hydrogen atom is -3.4eV. Find KE and PE of electron in the ground state.
The total energy of the electron in the first excited state of hydrogen is -3.4 eV . What is the kinetic energy of the electron in this state?
The total energy of an electron in the second excited state of the hydrogen atom is about -1.5 eV. The kinetic energy and potential energy of the electron in this state are:
The ground state energy of hydrogen atom is -13.6eV. What are P.E. and K.E. of electron in this state?
The energy of the electron in the ground state of hydrogen atom is -13.6 eV . Find the kinetic energy and potential energy of electron in this state.
PRADEEP-ATOMS AND NUCLEI-Assertion- Reason type question 12
