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Express 1 joule in eV. Taking 1a.m.u. =9...

Express 1 joule in eV. Taking 1a.m.u. `=931 MeV`, calculate the mass of `._6C^12`.

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`1eV=1.602xx10^(-19)"joule"`
`:. 1.602xx10^(-19)"joule"=1eV`
`1 "joule"=1/(1.602xx10^(-19))eV`,
`1 "joule" =6.242xx10^(18)eV`
(ii) form `E=mc^2`
`m=E/(c^2) :. 1 a.m.u. =(931xx1.602xx10^(-13))/((3xx10^8)^2)`
`=1.66xx10^(-27)kg`
Now, by defination, mass of `._6C^(12)=12 a.m.u.`
`=12xx1.657xx10^(-27)kg=1.99xx10^(-26)kg`
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