Home
Class 12
PHYSICS
The nuclear mass of .26F^(56) is 55.85u....

The nuclear mass of `._26F^(56)` is 55.85u. Calculate its nuclear density.

Text Solution

Verified by Experts

Here, mass m=55.85 u
`=55.85xx1.67xx10^(-27)kg`
Volume `V=4/3pi R^3=4/3pi(R_0A^(1//3))^3`
`=4/3 piR_0^3xxA`
`:.` Nuclear density, `rho=m/v=(3m)/(4piR_0^3A)`
`=(3xx55.85xx1.67xx10^(-27))/(4xx22/7(1.2xx10^(-15))^3xx56)`
`=2.29xx10^(17)kg//m^3`
Promotional Banner

Topper's Solved these Questions

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (II) very short answer 16|1 Videos

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (I) Short Answer questions 1|1 Videos

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos

Similar Questions

Explore conceptually related problems

The nuclear mass of ""_(13)Al^(26) is 26.9815 amu. Find its nuclear density.

Given the atomic mass of ""^(56)Fe is 55.93 u , find its nuclear density. [1 u = 1.66 xx 10^(-27) kg, R_(0) = 1.2 fm]

Assume that the nuclear mass is of the order of 10^(-27) kg and the nuclear radius is of the order of 10^(15)m . The nuclear density is of the order of

What is the order of nuclear density?

Obtain approximately the ratio of nuclear radii of ._26U^(56) and ._92U^(238) . What is the approximately ratio of their nuclear densities?

Given the mass of iron nucleus as 55.85u and A = 56, the nuclear density is (u = 1.66 xx 10 ^(-27) kg, r = 1.2 xx 10 ^(-15)m )

Calculate the nuclear density of ""_(26)Fe^(54) . Given that the nuclear mass of ""_(26)Fe^(54) is 53.9396 amu.

The nuclear radius of ._(8)O^(16) is 3 xx10^(-15) m . If an atomic mass unit is 1.67 xx 10^(-27) kg , then the nuclear density is approximately.

The calculated mass of ""_(20)Ca^(40) is 40.328 u. It releases 306.3 MeV energy in a nuclear process . Its isotopic mass is

The mass number of a nuclide is 64. What is its nuclear radius?