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Calculate the B.E./nucleon of .17Cl^(35)...

Calculate the B.E./nucleon of `._17Cl^(35)` nucleus. Given that of proton `=1.007825u`, mass of neutron `=1.008665 u`, mass of `._17Cl^(35)=34.980000u , 1u=931MeV`.

Text Solution

Verified by Experts

In `._17Cl^(35)`, no. of protons=17,
no. of neutrons `=35-17=18`.
Mass defect `=17m_p+18m_n-M_(Cl)`
`=17xx1.007825+18xx1.008665-34.980000`
`= 17.133025+18.155970-34.980000`
`=0.308995u`
`B.E//"nucleon"=(0.308995xx931)/35=8.22MeV//N`
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