Calculate binding energy per nucleon of `._83Bi^(209)`. Given that m `(._83Bi^(209))=208.980388am u`
`m("neutron") = 1.008665 am u`
`m ("proton") = 1.007825 am u`

Explanation

To calculate the binding energy per nucleon of the bismuth nucleus \( _{83}^{209}\text{Bi} \), we will follow these steps:

### Step 1: Determine the number of protons and neutrons
The atomic number (Z) of bismuth (Bi) is 83, which means it has 83 protons. The mass number (A) is 209, which represents the total number of nucleons (protons + neutrons).

To find the number of neutrons (N):
\[
N = A - Z = 209 - 83 = 126
...