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Find the minimum energy required to sepa...

Find the minimum energy required to separated a neutron form `._18Ar^(40)`. Given `M_n=1.008665 u` , mass of `._18Ar^(40)=39.962383u` and mass of `._18Ar^(39)=38.964314u`.

Text Solution

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The nuclear reaction involved is
`._18Ar^(40)` to `._18Ar^(39)+._0n^1`
Mass defect `=39.962383-(38.964314+1.008665)`
`Deltam=0.010596u`
`:.` Minimum separation energy required
`=Delta mxx931MeV`
`=0.010596xx931=9.86MeV`
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