A hypothetica atom has energy levels uniformaly separated by 1.3 eV. At a temperature 2500k, what is the ratio of number of atoms in 15th excited state to the number in 13 th excited state.
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It is known that in excited state x, no. of atoms, `N_x=N_0e^((E_x-E_0)//kT)` `:. (N_(15))/(N_(13))=e^(-(E_(15)-E_(13))//kT)` `=exp.[-(2xx1.3eV)/(kT)]` `=exp.[-(2.6xx1.6xx10^(-19))/(1.38xx10^(-23)xx2500)]` `(N_(15))/(N_(13))=exp.[-12]=1/(e^(12))=6.15xx10^-6`
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