A radioactive sample contains 2.2 mg of pure `._6C^(11)` , which has a life period of 1224s. Calculate (i) number of atoms present initially. (ii) the activity when `5 mu g` of the sample will be left.
Text Solution
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Number of `._6C^(11)` atoms in 11 g of sample `=6.023xx10^(23)` `:.` In `2.2 mg` sample, `N_0=(6.023xx10^(23))/11xx2.2xx10^(-3)` `=1.2xx10^(20)` and in `5 mu g` of sample `N=(6.023xx10^(23)xx5xx10^-6)/11=2.74xx10^(17)` Activity of the sample `=R=lambdaN=0.693/TN` `=(0.693xx2.74xx10^(17))/1224` `1.55xx10^(14)` disintegrate per sec.
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