The sequence of decay of radioactive nucleus is `D overset alphato D_1oversetbeta toD_2 oversetalpha toD_3`. If nucleon number and atomic number of `D_2` are 176 and 71 respectively, what are their values for D and `D_3`?
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As `alpha` is `._2He^4` and `beta` is `._-1e^0`, therefore, for D, mass no. `=176+0+4=180` charge numeber `=71-1+2=72` for `D_3`, mass no. `= 176 -4=172` charge no. `=71-2=69`
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