One Mev positron encounters one MeV electron travelling in opposite direction. What is the wavelength travelling in opposite direction. What is the wavelength of photons produced, given rest mass energy of electron or positron `=0.512MeV` ? Take `h=6.62xx10^(-34)J-s`.
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Two photons are produced when a positron annhilated an electron. i.e., `(._-1e^0)+(._1e^0)=2 gamma` Total energy involved =Rest mass energy +KE of both `=2(0.512+1)=2xx1.512MeV` `:.` Energy of each photon `=(2xx1.512)/2=1.512 MeV` `E=xx1.6xx10^(-13)J` As `E=(hc)/lambda` `:. lambda =(hc)/E=(6.62xx10^(-34)xx3xx10^8)/(1.512xx1.6xx10^(-13))m` `=8.21xx10^(-13)m`
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