The atomic mass of uranium `._(92)^(238)U` is `23.058 u`, that of throium` ._(90)^(234)Th` is `234.0436 u` and that of an alpha particle `._2^4He` is `4.006 u`, Determine the energy released when `alpha-decay` converts`._(92)^(238)U` into `._(92)^(238) U`. int `._(90)^(234)Th`.
Text Solution
Verified by Experts
The given nuclear reaction is `._92U^(238) to ._90Th^(234)+._2He^4` Mass defect, `Deltam=238.05079-234.04363-4.000260` `=0.00456 u` `:.` Energy released `=0.00456xx931.5MeV` `=4.25MeV`
Topper's Solved these Questions
ATOMS AND NUCLEI
PRADEEP|Exercise (II) very short answer 16|1 Videos
ATOMS AND NUCLEI
PRADEEP|Exercise (I) Short Answer questions 1|1 Videos
COMMUNICATION SYSTEMS
PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos
Similar Questions
Explore conceptually related problems
The atomic mass of thorium ._(90)^(234)Th is 234.04359 u , while that of protactinium ._(91)^(234)Pa is 234.04330 u . Find the energy released when beta decay changes overset(234)(90)Th into
The isotoic mass of ""_(92)^(238)U is 238.125 a.m.u. Its packing fraction is
""_(92)^(235)U, ""_(92)^(238)U and ""_(92)^(239)U are
By using the following atomic masses : ._(92)^(238)U = 238.05079u . ._(2)^(4)He = 4.00260u, ._(90)^(234)Th = 234.04363u . ._(1)^(1)H = 1.007834, ._(91)^(237)Pa = 237.065121u (i) Calculate the energy released during the alpha- decay of ._(92)^(238)U . (ii) Show that ._(92)^(238)U cannot spontaneously emit a proton.
What is the percentage of ""_(92) U ^(235) in ""_(92) U ^(238) ?
We are given the following atomic masses: ""_(93)Pu^(238) = 238.04954 u ""_(92)U^(234) = 234.04096 u ""_(2)He^(4) = 4.00260 u Calculate the kinetic energy associated with the alpha particle emitted during the conversion of ""_(94)Pu^(238) into ""_(92)U^(234)
Determine the number of protons and neutrons in ""_(92)U^(238) and ""_(90)Th^(234) .
Alpha decay of ._(92)^(238)U forms ._(90)^(234)Th . What kind of decay from ._(90)^(234)Th produces ._(84)^(234)Ac ?
PRADEEP-ATOMS AND NUCLEI-Assertion- Reason type question 12
