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Calculate the energy released when three...

Calculate the energy released when three alpha particles combine to form a `^12 C` nucleus. The atomic mass of `_2^4 He` is `4.002603 u`.

Text Solution

Verified by Experts

The nuclear reaction is
`3 ._2He^4 to ._6C^(12)+Q`
Mass defect `Delta m=3xx4.002604-12.000000`
`=0.007812u`
Energy released =`0.007812xx931MeV`
`=7.27MeV`
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