The energy released by fission of one `U^(235)` atom is 200 MeV. Calculate the energy released in kWh, when one gram of uranium undergoes fission.
Text Solution
AI Generated Solution
To solve the problem of calculating the energy released in kWh when one gram of uranium-235 undergoes fission, we can follow these steps:
### Step 1: Calculate the number of atoms in 1 gram of uranium-235.
The number of atoms can be calculated using Avogadro's number and the atomic mass of uranium-235.
\[
\text{Number of atoms} = \frac{\text{Avogadro's number}}{\text{Atomic mass}} = \frac{6.022 \times 10^{23}}{235}
\]
...
Topper's Solved these Questions
ATOMS AND NUCLEI
PRADEEP|Exercise (II) very short answer 16|1 Videos
ATOMS AND NUCLEI
PRADEEP|Exercise (I) Short Answer questions 1|1 Videos
COMMUNICATION SYSTEMS
PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos
Similar Questions
Explore conceptually related problems
The enegry released per fission of .^(235)u is nearly
An explosion of atomic bomb releases an energy of 7.6xx10^(13)J . If 200 MeV energy is released on fission of one .^(235)U atom calculate (i) the number of uranium atoms undergoing fission. (ii) the mass of uranium used in the atom bomb
What is the energy released by fassion of 1 g of U^(235) ? (Assume 200 Me V energy is liberated on fission of 1 nucleus)
(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)
The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is
The fission properties of ._84Pu^(239) are very similar to those of ._92U^(235) . The average energy released per fission is 180MeV . How much energy in MeV is released if all the atoms in 1kg of pure ._94Pu^(239) undergo fission.
The energy released by complete fission of one kilogram of ""^(235)U is equal to that released by complete burning of
The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :
Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))
PRADEEP-ATOMS AND NUCLEI-Assertion- Reason type question 12
