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You are given two nuclei .3X^7 and .3Y^4...

You are given two nuclei `._3X^7` and `._3Y^4`. Explain giving reasons, as to which one of the two nuclei is likely to be more stable?

Text Solution

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In case of `._3X^7`,
`=("neutron number")/("proton number")=(7-3)/3=1.33`
In case of `._3Y^4`,
`=("neutron number")/("proton number")=(4-3)/3=1/3=0.33`
for stability, this ration has to be close to one. Obviously, nuclues `._3X^7` is more stable than the nucleus `._3Y^4`.
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