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The sequence of decay of radioactive nuc...

The sequence of decay of radioactive nucleus is `Doversetalpha toD_1oversetbetatoD_2 overset alphatoD_3oversetalphatoD_4`
If nucleon number and atomic number of `D_2` are 176 and 71 respectively, what are their value of D and `D_4`?

Text Solution

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As mass number of each `alpha` particle is 4 units and its charge number 2 units, therefore, for `D_4`
`A=176-8=168`
`Z=71-4=67`
Now, charge no. of `beta` is -1 and its mass number
is zero, therefore, for D
`A=176+0+4=180`
`Z=71-1+2=72`
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