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In a typical unclear reaction, e.g. ""...

In a typical unclear reaction, e.g.
`""_(1)^(2)H+""_(1)^(2)H to ""_(2)^(3)He + n +3.27 Me V`,
although number of nucleons is conserved is conserved, yet energy is released. How ? Explain.
(b) Show that nuclear density in a given nucleus is independent of mass number A.

Answer

Step by step text solution for In a typical unclear reaction, e.g. ""_(1)^(2)H+""_(1)^(2)H to ""_(2)^(3)He + n +3.27 Me V, although number of nucleons is conserved is conserved, yet energy is released. How ? Explain. (b) Show that nuclear density in a given nucleus is independent of mass number A. by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

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Explore conceptually related problems

(a) In a typical nuclear reaction, e.g., " "_(1)^(2)H + " "_(1)^(2)H to " "_(2)^(3)He +n +3.27 MeV , although number of nucleons is conserved, yet energy is released. How ? Explain. (b) Show that nuclear density in a given nucleus is independent of mass number A.

(a) In a nuclear reaction ""_(2)^(3)He +""_(2)^(3)He to ""_(2)^(4)He+""_(1)^(1)H +""_(1)^(1)H +12.86 MeV, though the number of nucleons is conserved on both sides of the reaction, yet the energy is released. How? Explain. (b) Draw a plot of potential energy between a pair of nucleons as a function of their separation. Mark the regions where potential energy is (i) positive and (ii) negative.

Knowledge Check

  • In the nuclear reaction ""_(13)Al^(27)+""_(2)He^(4) to ""_(14)X^(30)+""_(1)H^(1), X is

    A
    Si
    B
    Al
    C
    Mg
    D
    P
  • ""_(1)H^(2)+""_(1)H^(2) to ""_(2)He^(3)+""_(0)n^(1) The above nuclear reaction is called

    A
    nuclear fission
    B
    nuclear fusion
    C
    artificial transmutation
    D
    spontaneous disintegration
  • A nuclear fussion reaction is given below : ._(1) H^(2) + ._(1)H^(2) to ._(2)He^(3) + n + 3.2 Me V How much energy will be generated when 2 kg of deuterons are fused :

    A
    `10^(30) eV`
    B
    ` 5 xx 10^(23) Me V`
    C
    `10^(22) Me V`
    D
    ` 10^(33) eV`
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