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Energy of an electron in an excited hydr...

Energy of an electron in an excited hydrogen atom is `-3.4eV`. Its angualr momentum will be: `h = 6.626 xx 10^(-34) J-s`.

Text Solution

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form `E=-13.6/(n^2)eV`, we find that
`-3.4=-13.6/(n^2)`
`n^2=(-13.6)/(-3.4)=4 , n=sqrt4=2`
According to Bohr's quantisation condition, angular momentum of electron in nth state is
`mvr=(nh)/(2pi)=(2xx6.6xx10^(-34))/(2xx3.14)`
`=2.11xx10^(-34)J-s`
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