The radius of innermost electron orbit of a hydrogen atom is `5.3xx10^(-11)m`. What are the radii of n=2 and n=3 orbits.?

Explanation

To find the radii of the n=2 and n=3 orbits of a hydrogen atom, we can use the formula for the radius of the electron orbit in a hydrogen atom:

\[ r_n = n^2 \times r_1 \]

where:
- \( r_n \) is the radius of the orbit for quantum number \( n \),
- \( r_1 \) is the radius of the innermost orbit (n=1), which is given as \( 5.3 \times 10^{-11} \, \text{m} \),
- \( n \) is the principal quantum number.
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