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Obtain the binding energy of a nitrogen ...

Obtain the binding energy of a nitrogen nucleus from the following data:
`m_H=1.00783u`,`m_N=1.00867u`,`m(._7^14N)=14.00307u`
Give your answer in units of MeV. [Remember `1u=931.5MeV//c^2`]

Text Solution

Verified by Experts

`._7N^(14)` nucleus contains 7 protons and 7neutrons.
`:.` Mass defect `(Deltam)=7m_H+7m_N -m_(N)=7xx1.00783+7xx1.00867-14.00307`
`=7.05481+7.06069-14.00307=0.11243u.`
Binding energy =`0.11243xx931MeV=104.67MeV`
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