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The half life of .38Sr^(90) is 28 years....

The half life of `._38Sr^(90)` is 28 years. What is disin. rate of 15g of this isotope?

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Here `T=28 years =28xx3.154xx10^7s`
As number of atoms in 90g of `._38Sr^(90)=6.023xx10^(23)`
`:.` Number of atoms in 15g of `._38Sr^(90)= (6.023xx10^(23))/90xx5/1000`, i.e, `N=1.0038xx10^(20)`
Rate of disint., `(dN)/(dt)=lambdaN=0.693/TN=(0.693xx1.0038xx10^(20))/(28xx3.154xx10^7)=7.877xx10^(10)Bq`
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