The radionuclide `._6C^(11)` decays according to `._6C^(11)to ._5B^(11) +e^(+) +v`: half life =20.3min. The maximum energy of the emitted positron is `0.960 MeV`. Given the mass values `m(._6C^(11))=11.011434u, m(._6B^(11))=11.009305u` Calculate Q and compare it with maximum energy of positron emitted.
Text Solution
AI Generated Solution
To solve the problem, we need to calculate the Q value of the decay process and compare it with the maximum energy of the emitted positron.
### Step 1: Write the decay equation
The decay of Carbon-11 can be represented as:
\[
_{6}^{11}C \rightarrow _{5}^{11}B + e^{+} + \nu
\]
...
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