Suppose, we think of fission of a `._26Fe^(56)` nucleus into two equal fragments `._13Al^(28)`. Is the fission energetically possible? Argue by working out Q of the process. Given `m(._26Fe^(56))=55.93494u, m(._13Al^(28))=27.98191 u.`

Explanation

To determine whether the fission of a \( _{26}^{56}\text{Fe} \) nucleus into two equal fragments of \( _{13}^{28}\text{Al} \) is energetically possible, we need to calculate the Q-value of the reaction. The Q-value is the difference in mass-energy between the reactants and the products. If the Q-value is positive, the reaction is energetically favorable.

### Step-by-Step Solution:

1. **Write the Reaction**:
The fission reaction can be represented as:
\[
_{26}^{56}\text{Fe} \rightarrow 2 \times _{13}^{28}\text{Al}
...