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The neutron separation energy is defined...

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separartion energy of the nuclei `._(20)Ca^(41)` and `._(13)Al^(27)` form the following data : `m(._20Ca^(40))=39.962591u` and `m(._(20)Ca^(41))=40.962278u`
`m(._(13)Al^(26))=25.986895u` and `m(._(13)Al^(27))=26.981541u`

Text Solution

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When nucleons is separated form `._(20)Ca^(41)`, we are left with `._(20)Ca^(40)` i.e. `._(20)Ca^(41)to._(20)Ca^(40)+._0n^1`
Now, mass defect `Deltam=m(._(20)Ca^(40))+m_n-m(._(20)Ca^(41))`
`=39.962591+1.008665-40.962278=0.008978a.m.u`
`:.` Neutron separation energy `=0.008978xx931MeV=8.362 MeV`
Similarly, `._(13)Al^(27)to._(13)Al^(26)+._0n^1`
`:.` Mass defect, `Deltam=m(._(13)Al^(26))+m_n-m(._(13)Al^(27))`
`25.986895+1.008665-26.981541=0.0138454u`
`:.` Neutron separation energy `=0.0138454xx931MeV=12.89MeV`
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