Home
Class 12
PHYSICS
Calculate and compare the energy release...

Calculate and compare the energy released by (a) fusion of 1.0kg of hydrogen deep within the sun, and (b) the fission of 1.0kg of `U^(235)` in a fission reactor.

Text Solution

Verified by Experts

In sun, four hydrogen nuclie fuse to form a helium nucleus with the release of 26MeV energy.
`:.` Energy released by fusion of 1kg of hydrogen `=(6xx10^(23)xx10^3)/4xx26MeV`
`E_1=39xx10^(26)MeV`
As energy released in fission of one atom of `._(92)U^(235)=200MeV`,
`:.` Energy released by fusion of 1kg of `._(92)U^(235)=(6xx10^(23)xx10^3)/235xx200 MeV`
`E_2=5.1xx10^(26)MeV`
`(E_1)/(E_2)=(39xx10^(26))/(5.1xx10^(26))=7.65`, i.e. energy released in fusion is 7.65 times the energy released in fission.
Promotional Banner

Topper's Solved these Questions

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (II) very short answer 16|1 Videos

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (I) Short Answer questions 1|1 Videos

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos

Similar Questions

Explore conceptually related problems

Energy released in fusion of 1 kg of deuterium nuclei.

The ratio of the amounts of energy released as a result of the fusion of 1 kg hydrogen (E_(1)) and fission of 1 kg of ._(92)U^(236)(E_(2)) will be

Calculate the energy released by fission from 2 g of .^(235)._(92)U in kWh . Given that the energy released per fission is 200 MeV .

Calculate the energy released by fission of 1 g of ._(92)^(235)U , assuming that an energy of 200 MeV is released by fission of each atom of .^(235)U . (Avogardo constant is = 6.023 xx 10^(26) kg mol^(-1) )

What is the energy released by fassion of 1 g of U^(235) ? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

Calculate the energy released by 1 g of natural uranium assuming 200 MeV is released in eaech fission event and that the fissionable isotope ^235 U has an abundance of 0.7% by weight in natural uranium.

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

How much energy is released when 2 mole of U^(235) is fission :