Would the bohr formula for the H-atom remain unchanged if proton had a change `(+4//3) e` and electron a change `(-3//4) e`, where `e = 1.6 xx 10^(-19) C`. Given reasons for you answer.
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In Bohr's formula, we say centripetel force `(m v^(2))/(r )` is provided by Coulomb's force of attraction between the nucleus (a proton) and revolving electron. The coulomb's force `prop (-e) (e) = - e^(2)`. If change on proton `= (+(4)/(3) e)` and change on electron `= (-(3)/(4) e)`, their product `((4)/(3) e) (-(3)/(4) e) = - e^(2)`, remains the same. And `e = 1.6 xx 10^(-19) C` in both the cases. Therefore, Bohr formula for H-atom shell remain unchanged.
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