Positronium is just like a H-atom with the proton replaced by the positively charged anti-particle of the electron (called the positron which is as massive as the electron). What would be the ground state energy of positronium ?
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In Bohr' s formula, `E_(n) = (-m e^(4))/(8 in_(0)^(2) n^(2)h^(2))` m is called the reduced mas. In case of hydrogen atom, `m = m_(e) =` mass of electron. for positronium : electron revolves around a positron, both mass `m_(e)`. Therefore, reduced mass `m = (m_(e) xx m_(e))/((m_(e) + m_(e))) = (m_(e))/(2) :. E_(n) = (-m_(e) e^(4))/(16 in_(0)^(2) n^(2) h^(2)) = - (13.6)/(2) eV = - 6.8 eV` This is the ground state energy of positronium.
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