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A nuclide 1 is said to be the mirror iso...

A nuclide 1 is said to be the mirror isobar of nuclide 2 if `A_(1)=N_(2)` and `Z_(2)=N_(1)`. (a) What nuclide is a mirror isobar of `._(11)^(23)Na`? (b) Which nuclide out of the two mirror isobars has greater binding energy and why?

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By defination, a nuclide 1 is said to be mirror isobar of nuclide 2, if `Z_(1)=N_(2) and Z_(2)=N_(1)`.
Now, in `._(11)Na^(23), Z_(1)=11, N_(1)=23-11=12`
`:.` Mirror isobars of `._(11)Na^(23)` is `._(12)Mg^(23)`, for which `Z_(2)=12` and `N_(2)=23-12=11`
As `._(12)Mg^(23)` contains even number of protons against `._(11)Na^(23)` which has odd number of protons, therefore `._(12)Mg^(23)` has greater binding energy than `._(11)Na^(23)`
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