An alpha particle of energy 4MeV is scattered through an angle of `180^(@)` by a gold foil (Z=79). Calculate the maximum volume in which positive charge of the atom is likely to be concetrated?

Answer

`7.7xx20^(-40)m^(3)`

Explanation

Maximum volume in which positive charge of atom is likely to be concentrated is
`V_(0)=4/3pir_(0)^(3)`
Calculate `r_(0)` form the usual formula.