If radius of the `_(13)^(27) Al` necleus is estimated to be `3.6` fermi then the radius of `_(52)^(125)Te` nucleus be nearly

Answer

6 fermi

Explanation

Here, `A_(1)=27, r_(1)=3.6 fermi, A_(2)=125, r_(2)=?`
As `(r_(2))/(r_(1))=((A_(2))/(A_(1)))^(1//3)=(125/27)^(1//3)=5/3`
`r_(2)=5/3r_(1)=5/3xx3.6=6.0 "fermi"`