The mass of a `a_3^7 Li` nucleus is `0.042 u` less than the sum of the masses of all its nucleons. The binding energy per nucleon of `._3^7 Li` nucleus is nearly.

Answer

`5.588 MeV//N`

Explanation

Here, `Deltam=0.042a.m.u`
BE=`Deltamxx931.5MeV`
`=0.042xx931.5MeV=39.123MeV`
BE/nucleon `=39.123/7=5.588MeV//N`