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Calculate the half life periode of a rad...

Calculate the half life periode of a radioactive substance if its activity drops to `1/16` th of its initial value of 30 yr.

Text Solution

Verified by Experts

The correct Answer is:
`7.5 yr`

`T=?, N/(N_(0))=1/16, t=30years`
As `N/(N_(0))=(1/2)^(n)=1/16=(1/2)^(4)`
`:. n=4=t/T,T=t/4=30/4=7.5 years`
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Knowledge Check

  • Half-life period of a radioactive substance is 6 h . After 24 h activity is 0.01 muC , what was the initial activity ?

    A
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    B
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    A
    20 s
    B
    40 s
    C
    60 s
    D
    80 s
  • The half-life of a radioactive substance is 3h and its activity is 1mu Ci . Then the activity after 9h will be (in mu Ci )-

    A
    `1/9`
    B
    `1/27`
    C
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    D
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