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The half life of radioactive Radon is 3....

The half life of radioactive Radon is `3.8 days` . The time at the end of which `(1)/(20) th` of the radon sample will remain undecayed is `(given log e = 0.4343 ) `

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The correct Answer is:
`16.43 days`
`N=N_(0)=-19/20N_(0)=1/20N_(0)`
Use `N/(N_(0))=(1/2)^(n) , t=nT`
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